Re: Split string into shell words?

[Kai Grossjohann]

Stefan Monnier <monnier@iro.umontreal.ca> writes:

> It's pretty nasty to do it right:
>
>   foo "bar $(baz "toto") titi"
>
> should turn into "foo" "bar $(baz \"toto\") titi".
> What do you need this for ?

I want to make it so that typing "vi foo" at the shell prompt (as in
M-x shell) does like C-x C-f foo RET.  Thus, I wrote
shell-integration.el (posted to gnu.emacs.sources).

The mode looks whether it knows the command typed as the first word on
the line and then invokes a lisp function, if so.  I thought it would
be good if that lisp function received a list of arguments.

That's why I wanted to split the current command line into words.

Now I have used the following workaround: each such lisp function
receives only a single string as its arg, which is the whole command
line.  The lisp functions then (normally) use the comint-arguments
function to extract the words they need.

Hm.  It seems that my approach was too simple-minded, as I can't say
"vi $(uname)" -- this will try to edit a file called "$(uname)" rather
than editing a file called "Linux".  So I guess I need to pass the
command to the shell for expansion first, then pass the result to the
Lisp function.

Kai