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Re: lisp question
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From: |
Malte Spiess |
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Subject: |
Re: lisp question |
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Date: |
Tue, 01 May 2007 15:24:16 +0200 |
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User-agent: |
Gnus/5.110006 (No Gnus v0.6) Emacs/22.0.95 (gnu/linux) |
Hartmut Figge <h.figge@gmx.de> writes:
> Brendan Halpin schribselte
>>A Soare <alinsoar@voila.fr> writes:
>
>>> Why e^0 evaluates to 1?
>>
>>x^0 is defined as 1 for all real values of x.
>
> Mhm, not if x is zero. In this case the result is not defined. IIRC. :)
That is really a matter of how you define it. Normally it's easier to
say that 0^0=1, it makes calculations easier.
> Hartmut
Greetings
Malte