Re: Easy way to rename files sequentially?

[reader]

Peter Dyballa <Peter_Dyballa@Web.DE> writes:

> Maybe in your case this works:
>
>       M-x replace-regexp RET ^.*$ RET \,(format "%03d%s" \# \&) RET
>
> i.e. use the complete original file name (\&) and prepend it by a
> zeroes padded three digit number (\# = number of already completed
> replacements, i.e. starting with 0). The format specification can of
> course contain additional text. But: dired does not understand \, nor
> \# in its regular expressions – or I am missing something!

How can this possibly do what the OP has asked about?  It fails in my
case but you seem to have known that \. or \# wouldn't work in dired.

  dired-string-replace-match: Invalid use of `\' in replacement text

So I guess I'm missing what the utility of your post was meant to be.