Re: Emacs regexp problem

[Pascal Bourguignon]

"mailpitches@email.com" <mailpitches@email.com> writes:

> Hello, I'm doing an emacs replace-regexp and the regexp behaves
> differently from how it behaves in Python, and also differently from
> how I expect.
>
> I'm trying to add quotes around the parameter in a function call.
> I.e.:
> func(param) should be converted to func('param')
>
> I use the following command:
> M-x replace-regexp [enter] get\((.*)\) [enter] get('\1')) [enter]
>
> and the result is func(param) is converted to func('(param)')
>
> Why are those extra parentheses appearing in there; is this an error
> on emacs' part?

Read the doc! (info "(emacs)Regexps")

emacs regexp are more like BRE than ERE in this respect.


Use: M-x replace-regexp RET get(\(.*\)) RET get('\1')) RET

-- 
__Pascal Bourguignon__                     http://www.informatimago.com/

READ THIS BEFORE OPENING PACKAGE: According to certain suggested
versions of the Grand Unified Theory, the primary particles
constituting this product may decay to nothingness within the next
four hundred million years.