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Re: Inserting output from a program into a buffer


From: Tim Johnson
Subject: Re: Inserting output from a program into a buffer
Date: Sun, 21 Feb 2010 10:45:04 -0600
User-agent: slrn/0.9.9p1 (Linux)

On 2010-02-21, Barry Margolin <barmar@alum.mit.edu> wrote:
> In article <slrnho1bpi.49k.tim@bart.johnson.com>,
>  Tim Johnson <tim@johnsons-web.com> wrote:
>
>> On 2010-02-21, Tim Landscheidt <tim@tim-landscheidt.de> wrote:
<.>> > original region.
>>   Hi Tim: 
>>      Thanks for the reply. I had found that command, but unfortunately
>>      replacing the region is the last thing I want to do. The end game is a
>>      "time card", as you might guess from the data structure and the data
>>      structure needs to remain intact.
>>      Thanks Again!
>
> If you use it without the C-u modifier, the output will be put in the 
> *Shell Output* buffer.  You could use M-x insert-buffer to copy the 
> output into the current buffer.
  :) It appears that while I was sleeping you all were working on my
        problem. It occurs to me that yanking the region and then 'inserting
        it after the output is captured should work. I will report on how that
        goes.
  Thanks
-- 
Tim 
tim@johnsons-web.com
http://www.akwebsoft.com


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