|
From: | ken |
Subject: | print out all members of a list |
Date: | Mon, 28 Feb 2011 10:20:20 -0500 |
User-agent: | Thunderbird 2.0.0.24 (X11/20101213) |
(car '("one" "two" "three")) prints out "one" ... the first of the list. How to print out all elements of the list (in order and with the double quotes around them? I'm actually looking just to substitute something for "car" and not write an entire function. Or is there no such thing? Thanks much.
[Prev in Thread] | Current Thread | [Next in Thread] |