Re: print out all members of a list

[Richard Riley]

"Pascal J. Bourguignon" <pjb@informatimago.com> writes:

> Andreas Röhler <andreas.roehler@easy-emacs.de> writes:
>
>> Am 28.02.2011 16:20, schrieb ken:
>>> (car '("one" "two" "three"))
>>>
>>> prints out "one" ... the first of the list.  How to print out all
>>> elements of the list (in order and with the double quotes around them?
>>> I'm actually looking just to substitute something for "car" and not
>>> write an entire function.  Or is there no such thing?
>>>
>>> Thanks much.
>>>
>>>
>>
>> and still a form delivering with doublequotes...
>>
>> (let ((my-list (list "one" "two" "three")))
>>     (dolist (elem my-list)
>>   (insert (format "\n\"%s\"" elem))))
>
> Why do you write broken code?

I'm intrigued. Do you get a bonus point for every time you are rude and
condescending to people looking for help or are patiently helping
others?