Re: print out all members of a list

[Andreas Röhler]

Am 01.03.2011 14:10, schrieb Pascal J. Bourguignon:
> Andreas Röhler<andreas.roehler@easy-emacs.de>  writes:
>
> > Am 28.02.2011 16:20, schrieb ken:
> > > (car '("one" "two" "three"))
> > >
> > > prints out "one" ... the first of the list.  How to print out all
> > > elements of the list (in order and with the double quotes around them?
> > > I'm actually looking just to substitute something for "car" and not
> > > write an entire function.  Or is there no such thing?
> > >
> > > Thanks much.
> >
> > and still a form delivering with doublequotes...
> >
> > (let ((my-list (list "one" "two" "three")))
> >      (dolist (elem my-list)
> >    (insert (format "\n\"%s\"" elem))))
>
> Why do you write broken code?
>
>      (let ((my-list (list "o\"n\"e" "t\"wo" "th\\\"ree")))
>         (dolist (elem my-list)
>            (insert (format "\n\"%s\"" elem))))
>
>      "o"n"e"
>      "t"wo"
>      "th\"ree"
>
>
> Is it not easier to write code that works?
>
>      (let ((my-list (list "o\"n\"e" "t\"wo" "th\\\"ree")))
>         (dolist (elem my-list)
>            (insert (format "\n%s" (prin1-to-string elem)))))
>
>      "o\"n\"e"
>      "t\"wo"
>      "th\\\"ree"

Ok, thanks, interesting point.

From there `concat' read better for me

(let ((my-list (list "o\"n\"e" "t\"wo" "th\\\"ree")))
       (dolist (elem my-list)
          (insert (concat "\n" (prin1-to-string elem)))))

(?) :-)