Re: Appending lists

[Emanuel Berg]

Jean Louis wrote:

> (let* ((list-1 '(a b c))
>         (list-2 (nconc list-1 '(1 2 3))))
>    (eq list-1 list-2)) ;; => t
>
> eq - Return t if the two args are the same Lisp object.
>
> And we talked how variable's value does not change... values
> or Lisp objects?

Again, the value, a reference to a cons cell, doesn't change.

Here I think what's demonstrated is that list-1 and list-2 are
the same, i.e. they both hold references to the same
cons cell. It seems `nconc' returns a reference to the first
cons sell of the new list, which is the first of list-1 as
well; and the new list was created by changing the cdr of
list-1's last element so that instead of holding nil (denoting
the end of the list) it holds a reference to the first cons
cell of "list-2"...

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