Re: How to read an integer from the minibuffer

[Emanuel Berg]

Yuri Khan wrote:

>> (defun string-to-number-number (str)
>>   (if (string= str "0")
>>       0
>>     (let ((num (string-to-number str)))
>>       (unless (zerop num)
>>         num) )))
>> ;; (string-to-number-number "10")
>> ;; (string-to-number-number "1.5")
>> ;; (string-to-number-number "0")
>> ;; (string-to-number-number "-1.5")
>> ;; (string-to-number-number "-10")
>> ;; (string-to-number-number "not a number") ; nil
>
> ‘string-to-number’ has one more deficiency — it ignores additional
> non-digit characters.
>
> M-: (string-to-number "123foo") ; 123

I know, I don't know if this is really a problem tho ...

Maybe it can even be thought of as a feature, e.g.

(string-to-number "89.8 cm") ; 89.8

> You cannot build anything strict on such a lax parser.

Don't know how strict we will get but if we identify and patch
the singularities it will be something if not strict then at
least something that is useful.

But sure I think it should be changed in the C source ...

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