Re: -include command and wildcards

[Tristan Van Berkom]

I use a semantic kindof like this:

SOURCES=$(patsubst $(SRCDIR)/%.c , %.c, $(wildcard $(SRCDIR)/*.c))

-include $(patsubst %.c, %.d, $(SOURCES))

actualy I also have an include file that _always_ exists that comes 
first so I avoid make
complaining about empty include statement.

Cheers,
                   -Tristan

TAZ Vukovic, Mirko wrote:

> I am having fun with a makefile for latex files.  For a file foo.tex, 
> the dependencies (figures, style files, etc) are stored in a file 
> foo.tex-d, whose contents are of the form:
>
> latexdeps= ... list of files ...
>
>  
>
> In my makefile I have
>
>  
>
> -insert foo.tex-d
>
>  
>
> to load the dependencies and then below
>
>  
>
> %.dvi: %.tex $(latexdeps)
>
>             $(latex) ...
>
>  
>
> for compilation and finally, I also have
>
>  
>
> %.tex-d: %.log
>
>             latexdeps ...
>
>  
>
> which will re-create the dependency file upon my explicit request.
>
>  
>
> So, currently my make file is generic as far as compilation goes, but 
> I have to hard-code the file that has to be -include-d.  In the 
> example above, I am including foo.tex-d, but all my other rules have 
> wildcards.  If I want to compile a different file, I have to change 
> the makefile -include commands to point to the new file.
>
>  
>
> Is there some way of doing the inclusion via wildcards?  Or shall I 
> call make via a script that will assign a variable when calling make, 
> and then use that variable in the -include command?
>
>  
>
> I'm new to make and compilation on unix. 
>
>  
>
> Thanks
>
>  
>
> Mirko Vukovic
>
> Tokyo Electron Arizona
>
> Gilbert Arizona
>
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