@echo name1 = $(name1) does not work

[Morten Gulbrandsen]

uname -a
Linux debian 2.4.27-2-386 #1 Wed Aug 17 09:33:35 UTC 2005 i686 GNU/Linux


make -v
GNU Make 3.80
Copyright (C) 2002  Free Software Foundation, Inc.
This is free software; see the source for copying conditions.
There is NO warranty; not even for MERCHANTABILITY or FITNESS FOR A
PARTICULAR PURPOSE.
                                     
                                        

make
cc -c -o helloworld.o helloworld.c
cc    -o helloworld helloworld.o



####### Unexpected result #####$

according to the manual

http://www.gnu.org/software/make/manual/html_chapter/make_3.html#SEC13

then you would expect to see this output:

    

name1 = Makefile
name2 = inc.mk


cat  inc.mk
helloworld: helloworld.o
       cc    -o $@ $<

helloworld.o: helloworld.c
       cc -c -o $@ $<

.PHONY: clean
clean:
       -rm -f helloworld helloworld.o


cat Makefile
name1 := $(word $(words $(MAKEFILE_LIST)),$(MAKEFILE_LIST))

include inc.mk

name2 := $(word $(words $(MAKEFILE_LIST)),$(MAKEFILE_LIST))

all:
       @echo name1 = $(name1)
       @echo name2 = $(name2)



what can I do ?

Am I doing  something wrong or is the manual
not up to date ?

             

best regards

Morten Gulbrandsen

        

        
                
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