Re: Post 3.81 $? handling

[John Graham-Cumming]

Paul D. Smith wrote:
> bar should appear in $? in both situations (with or without the ";")
> because in both situations, make has decided to rebuild "foo" because
> "bar" is "newer".
>
> So, the bug is that "bar" is not present in "$?" when it should be;
> basically, $? is only set to prerequisites that are newer than the
> target _AND_ that actually exist.  In this case, the prerequisite is
> considered newer, but doesn't exist.

Ah.  I hadn't realized that this was a bug and not a feature.  For some 
reason I thought that the current behaviour was intended and that the 
3.82 behaviour was a change in a feature and not a bug fix.

Now I get it.

John.