Re: problems with $$

[John Graham-Cumming]

PATTON, BILLY (SBCSI) wrote:
> I have the following example :
> INCLUDE := -Idogs -Ipigs -Isheep -Irats
>
> PC_TO_O = @echo $$(INCLUDE:-I=include\=)
>
> .PHONY : x
>
> define x
> x : ; $(PC_TO_O)
> endef
> $(eval $(call x))
>
> It need to print out
> include=dogs include=pigs include=sheep include=rats

1. A substitution reference $(X:A=B) change A to B for each A _at the 
end_ of a word in $(X).  Hence your substitution reference doesn't work. 
 If you fix that your example will work.

    PC_TO_O = @echo $$(patsubst -I%,include=%,$(INCLUDE))

2. I don't think you need $(eval $(call x)) at all.  Try doing

    INCLUDE := -Idogs -Ipigs -Isheep -Irats

    PC_TO_O = @echo $(patsubst -I%,include=%,$(INCLUDE))

    .PHONY : x

    define x
    x : ; $(PC_TO_O)
    endef

    $(x)

3. Since you only have one line in your rule for x you don't need define

    INCLUDE := -Idogs -Ipigs -Isheep -Irats

    PC_TO_O = @echo $(patsubst -I%,include=%,$(INCLUDE))

    .PHONY : x
    x = x : ; $(PC_TO_O)
    $(x)

John.
--
John Graham-Cumming
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