Re: flushing output in make

[Philip Guenther]

On 7/17/06, ma <address@hidden> wrote:
...
> What I understand from your explanation on how make process a target is
> that: . It first do all of the expanding. Assuming the following make file:
>
> modules= a.o b.o c.o
>
> mylib.lib: $(modules)
>     @echo starting...
>     $(foreach n, $(modules), $(shell $(AR) -qur $@ $(n)))
>
>
> Make first expanding it to something such as this:
>
> modules= a.o b.o c.o
>
> mylib.lib: a.o b.o c.o
>     @echo starting...
>     $(AR) -qur $@ a.o
>     $(AR) -qur $@ b.o
>     $(AR) -qur $@ c.o

No.  The the expansion of the $(shell) function is the output of the
specified command, so all the $(AR) commands are being invoked while
make is doing its expansion.


Philip Guenther