Re: Function to display a command without expanding variables

[Michael Morrell]

John,

My goal is to have a "nicer" verbose output.

Currently, if I have a Makefile with:

CC = gcc
CFLAGS = -DWHATEVER

foo.o: foo.c
   $(Q)$(CC) $(CFLAGS) -c $<

Then, when I call make with "Q=@", I will get just the output from the
compile, and when I call make with "Q=", I will get the output

  gcc -DWHATEVER -c foo.c

printed before the compiler output.

I want a way to have the verbose mode show me this instead:

CC = gcc
CFLAGS = -DWHATEVER
$(CC) $(CFLAGS) -c $<

before the compiler output (I'm not sure how I want to see $< handled).

That way, if I were to compare two such outputs from make with hundreds
of such compiles and where all I changed was the value of CFLAGS, I would
see just one line of difference.

Does that explain things better?

   Michael

--- John Graham-Cumming <address@hidden> wrote:

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> Hash: SHA1
> 
> Michael Morrell wrote:
> > I'm trying to write a function that will let me display a command
> without
> > expanding the variables.
> > 
> > This way, I can write:
> > 
> > x = 1
> > y = 2
> > 
> > all:
> >      $(call show-cmd, echo $(x) $(y))
> > 
> > and have the output be:
> > 
> > echo $(x) $(y)
> > 1 2
> > 
> > That is, I want to see the command I am executing but I want it in a
> > "symbolic" form.
> 
> 
> You can't do that directly with a $(call) because $(call) expands it's
> arguments before they are passed to the function.   You could do
> something like
> 
> a = echo $(x) $(y)
> 
> and then use $(value a) to get the unexpanded string.   What are you
> actually trying to achieve?
> 
> John.
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