Re: Naming object files according to target

[t-timmy]

Do you mind explaining how to extend your example so that I can compile
different targets using the same source file, like in my first question?

Let's say, how do I compile foo-debug.o, bar-debug.o, foo-release.o and
bar-release.o if I have different C flags for targets "debug" and "release"?

What makes this whole thing complicated is that make compares the C file
timestamp with the O file timestamp and according to that decides whether to
compile or not. So how can I make it listen to differently named object
files?

Thanks


Sam Ravnborg wrote:
> 
> On Sun, May 03, 2009 at 11:25:10AM -0700, t-timmy wrote:
>> 
>> Hello,
>> 
>> I know this may sound newbie-ish, but I really need some help.
>> 
>> I want to name each of my object files prefixed with the current target
>> name.
>> That way when I change targets, I won't have to recompile everything to
>> make
>> sure there is no residue from the previous compilation (which may have
>> been
>> for a different target).
>> 
>> For example:
>> 
>> target1: c_flags = -DSOMETHING
>> target1: main.o
>> 
>> target2: c_flags = -DSOMETHING_ELSE
>> target2: main.o
>> 
>> main.o:
>> gcc $(c_flags) etc...
>> 
>> The only way I can avoid recompiling every time is by manually making a
>> rule
>> for, let's say, target1-main.o and target2-main.o, but I have a lot of
>> source files and it's a real hassle.
> 
> May I suggest you to read up on static patters.
> It looks like this is what is needed here if I understood you correct.
> 
> Snip from the documentation:
>    Here is an example, which compiles each of `foo.o' and `bar.o' from
> the corresponding `.c' file:
> 
>      objects = foo.o bar.o
> 
>      all: $(objects)
> 
>      $(objects): %.o: %.c
>              $(CC) -c $(CFLAGS) $< -o $@
> 
> 
>       Sam
> 
> 
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> 
> 

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