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Re: Conditionals, step one
From: |
Derek Clegg |
Subject: |
Re: Conditionals, step one |
Date: |
Thu, 16 Sep 2010 11:15:07 -0700 |
On Sep 16, 2010, at 5:56 AM, Radly wrote:
> Problems like this make me feel like a beginner...
>
> I have a project that needs to detect OSTYPE and set LIBS and LIBDIRS
> accordingly, but I can't get basic conditionals working. This doesn't work
> on either Mac OSX or Ubuntu Linux; they both use Make 3.81. Here's a
> stripped-down demo of my problem:
>
> OS = $OSTYPE
>
> ifeq ($(value OS), darwin10.0)
> TXT = GOT_IT
> else
> TXT = MISSED_IT
> endif
>
> all:
> @echo OS = $(value OS)
> @echo $(TXT)
>
> And here's the printed output:
> OS = darwin10.0
> MISSED_IT
>
> I've tried multiple variations on the ifeq test, and they all fail,
> producing the "MISSED_IT" text.
>
> Surely I'm missing something that will be obvious to someone else. What
> might it be?
Use $(info ...) to print the value of your variables. You'll see that OS is
equal to STYPE, not what you intended. Do this instead:
OS = $(OSTYPE).
Derek
Re: Conditionals, step one, Paul Smith, 2010/09/16
Re: Conditionals, step one, Jean-Rene David, 2010/09/17