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RE: How does $(error) work?
From: |
Warlich, Christof |
Subject: |
RE: How does $(error) work? |
Date: |
Thu, 9 Dec 2010 15:12:19 +0100 |
Chris Cross wrote:
> Trying to understand how $(error) works. The manual says "error is
> generated whenever this function is evaluated." With the makefile below I
> would expect to see output from line1 of the recipe but only see output
> from $(error).
> # error.mk
> .PHONY: target
>
> target:
> @echo recipe line 1
> $(error debug exit recipe line 2)
>
> $ make -f error.mk
> error.mk:5: *** debug exit recipe line 2. Stop.
Make immediately terminates when it sees the $(error) function. And it
evaluates functions _before_ running any reciepe.
Just replace error with warning: Then, you'll see both the evaluation of the
$(warning) function (first!), and _then_ the execution of the reciepe.
Cheers,
Christof