RE: How to switch behaviour according to glibc version?

[David Aldrich]

Hi David

Thanks again for your help. However, I’m not quite there yet.

If I do:

verstr := $(shell ldd --version | head -1)
$(info glibc $(verstr) detected)

I see:

glibc ldd (Ubuntu EGLIBC 2.19-0ubuntu6.6) 2.19 detected

But if I do:

verstr := $(shell ldd --version | head -1 | awk '{print $NF}')
$(info glibc $(verstr) detected)

I see:

glibc  detected

So there is something wrong with the awk command. It works ok from the command 
line but not in the makefile.  Might the apostrophes be the problem?

Best regards

David


From: address@hidden [mailto:address@hidden On Behalf Of David Boyce
Sent: 05 April 2016 18:36
To: David Aldrich <address@hidden>
Cc: address@hidden
Subject: Re: How to switch behaviour according to glibc version?

Makefiles are divided between make syntax and shell (recipe) syntax. Here 
you're trying to use a shell command (echo) in a place that's not a recipe. 
Replace it with $(warning ...) which is the make-syntax equivalent.

On Tue, Apr 5, 2016 at 9:24 AM, David Aldrich 
<address@hidden<mailto:address@hidden>> wrote:
Hi David

Thanks for your answer to my question. I have one outstanding problem. Part of 
the makefile is now:

ifeq ($(DISTRO),debian)
  verstr := $(ldd --version | head -1 | awk '{print $NF}')
  @echo glibc $(verstr) detected
  ifneq ($(call version_ge,$(verstr),2.22),TRUE)
    @echo "Warning: system glibc is incompatible with Zodiac so using glibc 
from OPEN_SOURCE_LIBS"
    GLIBC=$(OPEN_SOURCE_LIBS)/glibc/v2_22/
    GLIBC_FLAGS= 
-Wl,-rpath=${GLIBC}:${GLIBC}/math:${GLIBC}/elf:${GLIBC}/dlfcn:${GLIBC}/nss:${GLIBC}/nis:${GLIBC}/rt:${GLIBC}/resolv:${GLIBC}/crypt:${GLIBC}/n$
  endif
endif

For the first echo statement I get:

Makefile:236: *** missing separator. Stop.

Please can you suggest how I should correct that line?

Best regards

David



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