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From: | Thomas Shores |
Subject: | Re: Evaluate the following series: |
Date: | Wed, 15 Aug 2012 12:33:26 -0500 |
User-agent: | Mozilla/5.0 (Windows NT 6.1; WOW64; rv:12.0) Gecko/20120428 Thunderbird/12.0.1 |
1^2 + 2^2 + ... + n^2 = n*(2*n+1)*(n+1)/6 which gives exact answer 338350, certainly less than a million. On 8/13/2012 2:02 PM, Przemek Klosowski wrote:
On 08/12/2012 02:45 AM, address@hidden wrote:1^2+2^2+3^2+...+100^2. Could this be correct, I'm getting sum=50005000?Back of the envelope says NO: you have 100 terms that are at most 100^2, so the sum cannot be larger than one million._______________________________________________ Help-octave mailing list address@hidden https://mailman.cae.wisc.edu/listinfo/help-octave
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