Re: fzero tolerance issue ... and a related bug

[Joza]

So related to all that above, how does one find the root of a function that
is always positive, or zero, but never negative? For instance, an absolute
value:  f(x) = abs(x - 2)

This has root 2, but I can't give it an initial bracket [x1,x2] since
f(x2)*f(x2) >= 0.
Indeed, how could fzero even find an initial bracket?

So how can one solve such a simple equation with fzero?



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