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From: | Joza |
Subject: | Re: Implementing a Jacobi iterative method for Ax=b |
Date: | Mon, 29 Oct 2012 06:16:38 -0700 (PDT) |
Here are A and b if you want to test it out! A = [ 3 12 0 -1 0 0; 4 0 31 1 0 0; 2 1 0 0 17 -3; 27 2 0 0 0 1; 0 0 0 -1 1 11; 0 0 0 24 -1 0 ] (6x6) b = [ 39 117 12 98 14 55]^T (6x1) -- View this message in context: http://octave.1599824.n4.nabble.com/Implementing-a-Jacobi-iterative-method-for-Ax-b-tp4645833p4645868.html Sent from the Octave - General mailing list archive at Nabble.com.
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