On Tue, Feb 19, 2013 at 5:35 PM, Tomas Dome <
address@hidden> wrote:
> I think no. Because my function is a parameter of my hessianmatrix function
> and can be any function. Isnt a specific analytic function.
>
> El feb 19, 2013 1:28 p.m., "Juan Pablo Carbajal" <
address@hidden>
> escribió:
>>
>> On Tue, Feb 19, 2013 at 5:23 PM, Tomas Dome <[hidden email]> wrote:
>>
>> > yes, i have the analytic _expression_ by a variable. i mean my function is
>> > like:
>> >
>> > function H = hessianMatrix(fx,x0)
>> >
>> > ...
>> >
>> > its ok?
>> >
>> >
>> > 2013/2/19 Juan Pablo Carbajal <[hidden email]>
>> >>
>> >> On Tue, Feb 19, 2013 at 5:09 PM, tomasdome <[hidden email]> wrote:
>> >> > hi, i'm trying to calculate the hessian matrix of a multivariable
>> >> > function
>> >> > (f(x,y,z,r) for example),
>> >> >
>> >> > how i can do it?
>> >> >
>> >> > i'm trying to make him with 2 for statements and the function "diff"
>> >> > but
>> >> > i
>> >> > think "diff" only accepts univariable functions like f(x).
>> >> >
>> >> > sorry , i'm a newbie in Octave
>> >> >
>> >> > thanks! :)
>> >> >
>> >> >
>> >> >
>> >> > --
>> >> > View this message in context:
>> >> >
>> >> >
http://octave.1599824.n4.nabble.com/how-to-calculate-hessian-matrix-tp4649981.html
>> >> > Sent from the Octave - General mailing list archive at Nabble.com.
>> >> > _______________________________________________
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>> >>
>> >> 1. Do you have an analytic _expression_ for f(·)?
>> >> 2. If not, do you have a set of known values for f(·)? Where was the
>> >> function evaluated to get those values?
>> >
>> >
>>
>> I meant, whether you know f(·) analytically, e.g.
>> f(x,y,z,r) = x^2 + y - sqrt(z)/r
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