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Re: Matching Equation to Data
From: |
PetrSt |
Subject: |
Re: Matching Equation to Data |
Date: |
Fri, 15 Mar 2013 05:02:28 -0700 (PDT) |
I'm not sure, if I understood the question, but if you want find vector p, so
that
A=[x,y,z,ones(length(x),1)];
B= zeros(length(x),1);
A*p=B;
Have you tried left division "p=A\B", for the first instance? See 8.3
Arithmetic Operators
<http://www.gnu.org/software/octave/doc/interpreter/Arithmetic-Ops.html#Arithmetic-Ops>
.
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