Re: How to extract all variables from a structure

[Terry Duell]

On Thu, 28 Mar 2013 21:34:46 +1100, Andy Buckle <address@hidden>  
wrote:

> On 28 March 2013 09:36, Terry Duell <address@hidden> wrote:


> > I see that I can use the function "getfield" to extract the structure
> > "data" from the structure "s".
> > Is there a neat way of extracting all the variables from "data", (ie. so
> > that they are simply unstructured variables) without having to  
> > separately
> > reference each?
> >
> > Cheers,
>
> I don't think it is possible. The best you can do is use fieldnames, and
> then go through them using getfield. If it's nested and you can't make
> assumptions about how it's nested, then make it recursive.

I'm not getting anywhere useful with this.
I can extract the inner structure, and get the fieldnames, as follows...

octave:2> s
s =

  scalar structure containing the fields:

    data =

      scalar structure containing the fields:

        a =  7040
        b =  237.60
        c =  244.20
        d =  150
        e =  3000
        f =  14.500
        g =  14.500
        h =  14.500


octave:3> data = getfield(s,"data");
octave:4> data
data =

  scalar structure containing the fields:

    a =  7040
    b =  237.60
    c =  244.20
    d =  150
    e =  3000
    f =  14.500
    g =  14.500
    h =  14.500

octave:5> list = fieldnames(data);
octave:6> list
list =
{
  [1,1] = a
  [2,1] = b
  [3,1] = c
  [4,1] = d
  [5,1] = e
  [6,1] = f
  [7,1] = g
  [8,1] = h
}
octave:7> newlist = cell2mat(list)
newlist =

a
b
c
d
e
f
g
h

...but get myself all tangled up when I try to use the fieldnames (list,  
or newlist) with the function "getfield" to extract all the fields from  
"data".
Can someone please give me a clue as to how I should tackle that?

Cheers,
--
Regards,
Terry Duell