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Re: sqp
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From: |
PetrSt |
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Subject: |
Re: sqp |
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Date: |
Fri, 5 Apr 2013 06:46:13 -0700 (PDT) |
The fourth input argument should be related to inequality constraint h(x) >=
0, so if x(1:6) are reals, then it could be something like this
h=@(x) (1.85.*x(1:3,1) - x(4:6,1));
If you insist on the inequality h(x) > 0, then adding eps() should do the
job
h=@(x) (1.85.*x(1:3,1) - x(4:6,1)-eps());
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- sqp, Urs Hackstein, 2013/04/05