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RE: Convert array to function
From: |
Allen.Windhorn |
Subject: |
RE: Convert array to function |
Date: |
Fri, 19 Dec 2014 14:56:38 +0000 |
Marco,
> -----Original Message-----
> From: address@hidden
>
> I have a curve that is described as a vector v with n-elements,
> each containing a pair:
>
> v=[0,0; 2,2; 4,2; 6,6; 10,6]
>
> ASCII-art visualised:
>
> ^
> |
> 10|
> |
> 8|
> |
> 6| xxxxxxxxx
> | x
> 4| x
> | x
> 2| xxxxx
> | x
> +---------------------->
> 0 2 4 6 8 10
>
> I am only interested in the x-range [0:10] meaning the values below
> 0 and above 10 can be ignored.
>
> Vector v is given and I have to define a function that evaluates to
> the points described by the vector. The points are always connected
> by straight lines. So the function should (with the example values
> for v as stated above) at point 1 evaluate to 1, at point 2
> evaluate to 2, at point 8 evaluate to 6, etc.
>
> The pairs are not necessarily equally spaced and the number of
> elements in v is not constant. (This will be automated and the v is
> the input I receive.)
>
> The question: Is there an octave function which I can feed the
> vector with pairs (v) and obtain a function which I can evaluate at
> any point within the range?
Linear interpolation using interp1 works.
octave:3> v=[0,0; 2,2; 4,2; 6,6; 10,6]
v =
0 0
2 2
4 2
6 6
10 6
% Split the vector into x and y parts:
octave:4> x = v(:,1)
xx =
0
2
4
6
10
octave:5> y = v(:,2)
yy =
0
2
2
6
6
% Make a function from the table:
octave:11> f = @(x) interp1(xx, yy, x);
% See if it works:
octave:11> x = 0:0.5:10
octave:12> y = f(x);
octave:13> plot(x,y)
% Success!
Regards,
Allen