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Re: lsode use
From: |
Céline |
Subject: |
Re: lsode use |
Date: |
Wed, 26 Aug 2015 01:36:31 -0700 (PDT) |
In fact, my J values are different at each time t and are calculated
separately at each time.
So I need, each time, to give my J value to my ODE to be able to resolve
it...
I've tried your advices, but I do probably something wrong since it does not
work at all...
Here is the code of the loop (I've all the initialization of parameters and
variables before this):
for t=0:step:ts
x=@(X0,J) humsolide(X0,t,J);
[X, ISTATE, MSG]=lsode(x,X0,temps);
psat=psat0*exp(-(Lm/Rg)*((1/T)-(1/T0)));
if X(i)>=Xc
%evaporation rate calculation
J=a*Mw*ke*((psat/(Rg*T))-(p/(Rg*T))*(Y/((Mw/Ma)+Y)));
elseif X(i)<=Xc
%parameters calculation
Ri=R*(((X-Xr)/(Xc-Xr))^(1/3));
ki=((eps*D)/(tau*((R)^2)))*(1/((1/Ri)-(1/R)));
%evaporation rate calculation
J=a*Mw*(1/((1/ke)+(1/ki)))*((psat/(Rg*T))-(p/(Rg*T))*(Y/((Mw/Ma)+Y)));
end
Y=((Ms*J)/G)+Y0;
T=T0-((Ms*J*Lk)/(cpa*G));
%Adding the results in "results matrix"
Yres=[Yres;Y];
Jres=[Jres;J];
i+=1;
end
And my function humsolide:
function XDOT=humsolide(X0,t,J)
XDOT=-J;
endfunction
Do you know what's wrong ?
--
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- lsode use, Céline, 2015/08/25
- Re: lsode use, Doug Stewart, 2015/08/25
- Re: lsode use, Céline, 2015/08/25
- Re: lsode use, Olaf Till, 2015/08/25
- Re: lsode use, Céline, 2015/08/26
- Re: lsode use, Juan Pablo Carbajal, 2015/08/26
- Re: lsode use,
Céline <=
- Re: lsode use, Juan Pablo Carbajal, 2015/08/26
- Re: lsode use, Céline, 2015/08/26
- Re: lsode use, Juan Pablo Carbajal, 2015/08/26
- RE: lsode use, Pirson Céline, 2015/08/26
- Re: lsode use, Juan Pablo Carbajal, 2015/08/26
- Re: lsode use, Céline, 2015/08/26
- Re: lsode use, Juan Pablo Carbajal, 2015/08/26