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Re: Plotting the frequency response of a filter in "real" Hz
From: |
Maynard Wright |
Subject: |
Re: Plotting the frequency response of a filter in "real" Hz |
Date: |
Fri, 22 Apr 2016 17:25:40 -0700 |
User-agent: |
KMail/4.13.3 (Linux/3.16.0-30-generic; KDE/4.13.3; i686; ; ) |
> @ Maynard Wright
>
> I should have been more specific when I said I had just started in
> filter desing. This is a course for a Computer Engineering degree.
> Which means that I will deal with filter design until 18th of May, and
> then I'll probably forget about it for the rest of my life. While this
> course is provided by an Electric Engineering teacher, since we don't
> have any Electric Engineering students this semester, our teacher have
> encouraged us to stick to the built in functions to solve problems and
> we barely scratched the surface of the mathematics involved.
>
> Having said that, I have no idea where is the filter in the code you posted.
The filter is in the line
loss = abs((12000 ./ (12000 .+ 1j .* w)) .^ 7);
It's an arbitrary, "pulled from air" low pass filter that I stuck in the code
(not necessarily easily realizable) to provide a relatively flat passband and a
sharp cutoff to illustrate the effect of scaling the x axis from radian
frequency to frequency in Hz. You should be able to use the scaling
technique (divide by 2 * pi) with the amplitude response of any filter.
Maynard Wright
- Re: Plotting the frequency response of a filter in "real" Hz, (continued)
Re: Plotting the frequency response of a filter in "real" Hz, Sergei Steshenko, 2016/04/21
Re: Plotting the frequency response of a filter in "real" Hz, Sergei Steshenko, 2016/04/21
Plotting the frequency response of a filter in "real" Hz, Ericbarnhill, 2016/04/24
Re: Plotting the frequency response of a filter in "real" Hz, Sergei Steshenko, 2016/04/25