Re: (no subject)

[Lester Anderson]

Hello kai,

Thanks for the suggestion. The function handle did not help. I did
Google the syntax which came up with another version:

x = fzero(fun,x0,options,P1,P2,...)

where additional parameters (P1, P2, P3 etc.) could be used. I suspect
that the code is using this ?older version. I found a link to this
code version: 
http://opg1.ucsd.edu/~sio221/SIO_221A_2009/SIO_221_Data/Matlab5/Toolbox/matlab/funfun/fzero.m
which suggests it was in v5.

Lester



On 9 June 2016 at 15:56, siko1056 <address@hidden> wrote:
> Hi,
>
> Maybe try the function handle version:
>
> yy = fzero(@allequ,Y2(j,i),options,Y1(j,i),zb(j),zt(j),surpor(j),c(j));
>
> if "allequ" was a function in Octaves search path. And what are all those
> values in the end Y1(j,i),zb(j),zt(j),surpor(j),c(j)? fzero accepts only
> three, as pointed out by the error message.
>
> HTH, Kai
>
>
>
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