Re: 1 i 2

[slaythemall]

Ostatnie poprawki:
function [i, w] = zad_2()       
        suma = 0;
        n = 1;
        
        while (1)
                w = n * sqrt(n + 3) /(2^n);
                suma += w;
                
                if (suma > 4.8)
                        w = (n - 1) * sqrt(n + 2) /(2^(n - 1));
                        i = n - 1;
                        return;
                endif
                
                n += 1;
        endwhile
endfunction


teraz powinno być już dobrze




--
View this message in context: 
http://octave.1599824.n4.nabble.com/1-i-2-tp4677888p4677906.html
Sent from the Octave - General mailing list archive at Nabble.com.