R is of the same order of magnitude as 1e4. So dot(R,cross(R,V)) is of the
same order of magnitude as 1e8. 1e8 times octave eps is about 1e-8.
________________________________________
From: Help-octave address@hidden on behalf of Thomas D. Dean address@hidden
Sent: Saturday, July 16, 2016 1:35 PM
To: address@hidden
Subject: Big Loss of Precision
The cross product of two vectors is orthogonal to both. The dot product
of two orthogonal vectors is zero.
This is not an octave problem, just an ill-formed situation.
octave:1405> printf(" %.20f\n",V);
3.99120302628332668249
-0.91842329903575536942
1.29246846883179156151
octave:1406> printf(" %.20f\n",R);
-1518.35794621729837672319
-4017.17627231122196462820
4816.75939627815478161210
octave:1407> dot(cross(R,V),R)
ans = 1.4901e-08
octave:1408> dot(cross(R,V),V)
ans = 3.6380e-12
cross has 6 multiplications and 3 add/subtract
dot has 3 multiplications and 3 add/subtract
Octave eps is 2.2204e-16
machine eps is 1.11022e-16 (quadmath 1.925930e-34).
This case has a very serious loss of precision!
Tom Dean