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From: | Martin Kunz |
Subject: | Re: Help in leasqr |
Date: | Mon, 29 Aug 2016 08:55:51 +0200 |
User-agent: | Mozilla/5.0 (Windows NT 6.1; WOW64; rv:45.0) Gecko/20100101 Thunderbird/45.2.0 |
Am 26.08.2016 um 17:36 schrieb Bharath
R:
Maybe I am misunderstanding the task, but if you have T measured, you can calculate dT/dt with just
Now you have your lefthand side (it's one element shorter than T, handle this in a sensible way, e.g. by appending something to y or discarding one element from T later on) and might be able to use leasqr as before. HTH, Martin |
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