Re: deleting column/row from interval Matrice

[karamov]

Hi, 
Thanks for your answer, I constructed the following function:

function [c] = removei (b, i)#where i is the positition of the column vector
of intervals
  n=b(:,(i+1):size(b)(2))
  m=b(:,(1:(i-1)))
  c=[m,n]
endfunction

when my function is running(containing removei) I'm getting the following
output:

n = 2<C3><97>0 interval matrix

m = 2<C3><97>0 interval matrix

c = 2<C3><97>0 interval matrix

SetBoxes = 2<C3><97>0 interval matrix

Setboxes = 2<C3><97>0 interval matrix

Clearboxes = 2<C3><97>1 interval vector

Can I get rid of the  "<C3><97>", and can I simply remove the display of
those intermediate values during the run of my function? because it's taking
too long to get to the result




--
View this message in context: 
http://octave.1599824.n4.nabble.com/deleting-column-row-from-interval-Matrice-tp4680529p4680540.html
Sent from the Octave - General mailing list archive at Nabble.com.