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Re: c2d output Interpretation
From: |
Sergei Steshenko |
Subject: |
Re: c2d output Interpretation |
Date: |
Mon, 20 Feb 2017 21:51:40 +0000 (UTC) |
From: Nicholas Oleksinski <address@hidden>
To: address@hidden
Sent: Monday, February 20, 2017 7:00 PM
Subject: c2d output Interpretation
Hi:
I am trying to design a digital phase lead compensator using the c2d function
in the Octave 4.0.0 control package.
The output of the b & a coefficients I fed in looks like this:
7.474 z^2 - 14.29 z + 6.829
y1: ---------------------------
z^2 - 1.52 z + 0.5772
I noticed a couple things about this output:
1) The powers of the 'a' coefficients start positive. Does that not make this
system non-causal?
2) Why is this discrete time LTI model represented as "y1" and not "H(z)"? I
fed in the coefficients of H(s) by running c2d this way:
comp_tf = tf(gain*numc,denc); %create the s domain LTI transfer function
comp_tf_d = c2d(comp_tf,0.001); % sample at 1kHz
Thanks
_______________________________________________
By dividing both the numerator and denominator by z^2 you'll get an equivalent
expression with non-positive powers of z.
--Sergei.