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Re: Doubt octave usage to calculate

From: Doug Stewart
Subject: Re: Doubt octave usage to calculate
Date: Sun, 28 May 2017 10:08:47 -0400


On Sun, May 28, 2017 at 9:17 AM, qdoqwj <address@hidden> wrote:
Calculation of ln (2) using numerical series:
      100
Y5= ∑= 1/(2n + 1)*(2n+2)
      n=0



try this
Y5=0;
for n=0:100
  Y5=Y5+ 1/((2*n+1)*(2*n+2));
endfor
Y5 


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