Re: Struggling to write t0 from sometime ago

[shall689]

According to the documentation, the clock function doesn't have any
parameters.

Why not subtract their datenum value from each other to get the total number
of days. 

Function File: days = datenum (datevec)
Function File: days = datenum (year, month, day)
Function File: days = datenum (year, month, day, hour)
Function File: days = datenum (year, month, day, hour, minute)
Function File: days = datenum (year, month, day, hour, minute, second)
Function File: days = datenum ("datestr")
Function File: days = datenum ("datestr", f)
Function File: days = datenum ("datestr", p)
Function File: [days, secs] = datenum (…)

Stephen



--
View this message in context: 
http://octave.1599824.n4.nabble.com/Struggling-to-write-t0-from-sometime-ago-tp4684525p4684529.html
Sent from the Octave - General mailing list archive at Nabble.com.