Re: oct file ; problem with argument checking

[arnaud Lejeune]

Le 22/09/2017 à 13:24, Doug Stewart a écrit :

On Fri, Sep 22, 2017 at 6:53 AM, arnaud Lejeune <address@hidden> wrote:

Hello,

Using octave version = 3.8.0, I begin to play with octfiles.

I would check if the first argument of my function is an integer.

My toto.cc file contains :

DEFUN_DLD ( toto, args, nargout , "AIDE fonction toto")
{

    if ( ! args(0).is_integer_type() )
        error("Non integer value \n");

    const int dimension = args(0).int_value();
    octave_stdout << " DIMENSION " << dimension << std::endl;

}

When I run the .oct version of toto in octave with :

[x,y] = toto(2)

I get :

error: Non integer value
 DIMENSION 0

Obviously, that's not what I expect.

Being less ambitious, I check if my first arg is a scalar with "is_scalar_type()" instead of "is_integer_type"

DEFUN_DLD ( toto, args, nargout , "AIDE fonction toto")
{

    if ( ! args(0).is_scalar_type() )
        error("Non scalar value \n");

    const int dimension = args(0).int_value();
    octave_stdout << " DIMENSION " << dimension << std::endl;

}

Runing

[x,y] = toto(2)

Then It works and I get as expected

 DIMENSION 2

But I want to be sure my scalar type is an integer one.

Please could you help me and tell me what's wrong in my integer type checking with "is_integer_type" ?


Thanks for your help


Arnaud



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I am not sure of my answer but you can try

help int8

[x,y] = toto(int8(2))

--

DAS

ok

it works with int8(2) but isn't any member of "octave_value" that recognizes "2" as an integer when the user writes
[x,y] = toto( 2 )

Thanks for your help

Arnaud