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From: | Doug Stewart |
Subject: | Re: building dynamic ranges from matrix |
Date: | Tue, 21 Nov 2017 14:08:26 -0500 |
Example had an error it in. Should readrange_start_end = [1,5 ; 4 7];
should produce a vector containing [1:5,4:7], The final result being
[1,2,3,4,5,4,5,6,7].On Nov 21, 2017 12:47 PM, "AG" <address@hidden> wrote:
Here is my problem.
Given a N X 2 matric, build a single vector that contains the range of
numbers between (:,1) and (:,2).
For example:
range_start_end = [1,5 ; 4 7];
should produce a vector containing [1:5,2:4], The final result being
[1,2,3,4,5,4,5,6,7]. I am trying to do this with just simple matrix
operation if possible- no if's then's array functions etc.
I have tried this a few ways but can't seem to get it to work.. so I'd love
to hear any ideas.
-Much appreciated!
--
Sent from: http://octave.1599824.n4.nabble.com/Octave-General-f1599825. html
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