Re: building dynamic ranges from matrix

[avlas]

El dimarts, 21 de novembre de 2017, a les 18:46:57 EST, AG va escriure:

  Much appreciated.   The only challenge with this is it uses an array fun -
  which I was trying to avoid since I have a LOT of data and arrayfun seems to
  be slower due to using loops in its implementation. What provided is good
  because it generalizes to any number of rows.  At runtime, the array of
  range start end numbers is build and the number of rows is unknown so I
  can't do something like:
  
  rse = [1,5 ; 4 7];
  a=[rse(1,1) : rse(1,2) , rse(2,1):rse(2,2)]
  which was proposed by Doug.
  
  Perhaps this can't be done without looping.
  
  
  
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Sounds good. I thought it was for an arbitrary N in:

> Given a N X 2 matric, build a single vector that contains the range of
> numbers between (:,1) and (:,2). 

a.