Re: Simple Time Formatted Plot Problem

[Fritz Sonnichsen]

Thanks Ian.
  the syntax is close but actually must contain a vector:   axis([-inf inf 0 10]);
This works nicely---a good tip

fritz

On 3/2/2018 8:25 PM, Ian McCallion wrote:

Another way may be to let octave chose the axis ranges. Not at computer, but I think you need axis(-inf inf 0 10); 

Cheers... Ian

On 3 Mar 2018 00:57, "Fritz Sonnichsen" <address@hidden> wrote:

Mike. That worked. Still curious why Marco's approach works for him but not on my machine. I am working on a win machine today-maybe something about the way it handles floating point etc.
   I will use your approach-it would be nice if the Octave team would incorporate this into their code at some point so it is less "patched together". I would expect plotting time series is pretty common and something a little more streamlined would be nice. I vaguely recall that Matlab was similarly afflicted.

Thanks again both of you for your help!
Fritz

On 3/2/2018 1:02 PM, Mike Miller wrote:

On Fri, Mar 02, 2018 at 18:14:44 +0100, Marco Atzeri wrote:

without the axis, it works for me.
Use the "graphics_toolkit gnuplot" as fltk has problem on
numbers too near and large (due to resolution on float)

Or subtract away the irrelevant date part of the datenum values

    xdatenum = xdatenum - datenum ([2018, 1, 1, 0, 0, 0]);

I thought we had a FAQ entry about this, but I don't see one.

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Join us March 12-15 at CERN near Geneva
Switzerland for OctConf 2018.  More info:
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