Re: Filling the gaps in data arrays

[Przemek Klosowski]

On 07/12/2018 04:36 AM, Mat086 wrote:
> dx = x(2)-x(1);
> Y = zeros(1,length([min(x):dx:max(x)]));
> X = [min(x):dx:max(x)];
> for k=1:length(x)
>    indx = find(X==x(k));
>    Y(k) = y(index);
> endfor
> plot(x,y,'b-'); hold on; plot(X,Y,'-o');

you mean  Y(k) = y(indx); , right?

And no, it won't work in Matlab either because you are doing exact 
floating point comparisons on calculated values, so any roundoff will 
trip you up---check for yourself, X==X(3) returns matches, but X==x(3) 
probably doesn't.

You said that "In order to analyze such kind of data with another 
software I need to create X and Y vectors without holes". What is 
exactly the assumption there? Is the original dataset sampled on a 
regular grid, and the non-zero values are dropped?

It seems to me that the best solution for you would be to interpolate 
your data onto a regular grid, perhaps like this:

dx=x(2)-x(1);

plot(x,y,'x',X=min(x):dx:max(x),interp1(x,y,X))