assign value different position in array

[LucaLuca]

hello .. I reformulated the post with better examples

a = 

   NaN   NaN   NaN 
   NaN   NaN   NaN 
   NaN   NaN   NaN 

i want to assign value 0 to last end index position(v) 

v is position array

v = 

   2   1   3  (idx 2..idx 1..idx 3)
then :

2===> position n. 2 and n.3 =0   (last 2 element =0) 
1===> position n. 3=0    (last 1 element =0) 
3===> position n.1 and n.2 and n3=0  (last 3 element =0) 


the result :

=Nan   0   0   
=Nan  Nan  0   
=  0   0  0   

it's possible to do it avoid loop?





--
Sent from: http://octave.1599824.n4.nabble.com/Octave-General-f1599825.html