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RE: Round function
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From: |
Windhorn, Allen E [ACIM/LSA/MKT] |
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Subject: |
RE: Round function |
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Date: |
Fri, 16 Nov 2018 14:48:31 +0000 |
-----Original Message-----
From: Help-octave [mailto:address@hidden On Behalf Of Juan Pablo Carbajal
> This is actually an easy fix,
> new_round = @(x, n=0) round (x * 10^n) * 10^(-n)
>> new_round(pi, 1.5)
ans = 3.1307
Maybe new_round = @(x, n=0) round (x * 10^round(n)) * 10^(-round(n))?
Depending on what you expect it to do.
Regards,
Allen