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Re: Find egual number
From: |
Przemek Klosowski |
Subject: |
Re: Find egual number |
Date: |
Mon, 11 Feb 2019 14:38:46 -0500 |
User-agent: |
Mozilla/5.0 (X11; Linux x86_64; rv:60.0) Gecko/20100101 Thunderbird/60.2.1 |
On 2/9/19 5:58 AM, LucaLuca wrote:
f=[1 2 3 4 4 7 7 6 8 5]
it's possible to find >1 egual element? i want to know this position
f(4)=4 f(5)=4
f(6)=7 f(7)=7
Ans=4,5
6,7
I am genuinely curious---there's what looks like to be a group of
Italian gentlemen:
address@hidden
address@hidden
address@hidden
that regularly ask about Octave problems that, to me, share some common
characteristics, in that they explore the intricacies of syntax, in ways
that don't seem to be connected to actual practical problems. To me, it
looks like either someone's exploration of intricacies of Matlab, or a
series of homework etudes. It actually occurred to me that it could be a
Google algorithm similar to Alpha Zero
http://science.sciencemag.org/content/362/6419/1140 , trying to learn
mathematical computing :), especially since when I tried to answer one
of them (the last one) directly the email address bounced.
But, hey, let's play along. I am not sure that I understand the problem
as stated above but maybe something along the lines of
k=1:length(f)
find(f(k)==k)
or
find(f(k)!=k)
would be a solution.