Re: help - two different syntaxes produce different results -typo in previous

[Pantxo]

Carlo de Falco-2 wrote
> To get the same result in the two cases above you should modify the first
> one as follows:
> 
>>> v = [68   73   77   85
>    95   85  104   99
>    68  181  162   92
>    98  130  123   93
>    94   87   87   88];
>>> [a, b]= find(v>100);
>>> ab = sub2ind (size (v), a, b);
>>> v(a,b)= 0;

As a side remark, you could also obtain the correct result with a third
indexing form, namely "logical indexing", which is often faster since it
avoids the "find" step:

v = [68   73   77   85
   95   85  104   99
   68  181  162   92
   98  130  123   93
   94   87   87   88];
v(v>100) = 0

Pantxo




--
Sent from: https://octave.1599824.n4.nabble.com/Octave-General-f1599825.html