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From: | Doug Stewart |
Subject: | Re: pade function in Octave? |
Date: | Thu, 31 Oct 2019 17:43:21 -0400 |
Thank you Doug for your response!
I would like to fit some data to a curve using pade approximation. I have
used polyfit and it worked reasonably well, but I think pade may give the
most accurate fit equation.
This is the data I would like to fit -
2.35504, 0.87524, 0.76141, 0.87769, 3.08380, 1.01227, 0.77118, 4.92401,
0.68878 , 0.87189 , 2.60315 0.70099 , 0.85419 , 9.17908, 1.07910 ,
0.80322 , 2.39624 , 3.36853 , 1.19812 , 0.66193 , 0.78033
When I use this data as an argument to padecoef, I get the following
exception -
error: padecoef: T must be a non-negative scalar
error: called from
padecoef at line 92 column 5
padefunction at line 12 column 12
Do I have to convert the data to some form?
Please let me know.
Thank you,
Vivek.
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