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[Linphone-users] No dtmf generator when attempting to play dtmf [Python]

From: Kenneth Clive
Subject: [Linphone-users] No dtmf generator when attempting to play dtmf [Python]
Date: Wed, 16 Sep 2015 13:39:53 +0000

I am having trouble generating dtmf tones when I receive a call.  Here is what my call_state_changed callback looks like (this is in Python):


    def call_state_changed(core, call, state, message):

        logging.warning("call_state_changed: " + str(state) + ", " + message)


        if state == linphone.CallState.IncomingReceived:

            print "***Incoming call on " + core.identity


            time.sleep(10)      # wait 10 seconds for audio to play

        elif state == linphone.CallState.Connected:


            core.play_dtmf(1,300)    # press 1 for 300 ms to acknowledge the alert


            print "***Call successfully answered on " + core.identity

        elif state == linphone.CallState.End:

            print "***Call successfully hung up on " + core.identity

        elif state == linphone.CallState.Error:

            logging.error("call_state_changed: " + core.identity + ", " + str(state) + ", " + message)


When I am handling the linphone.CallState.Connected case, I am starting the dtmf stream, playing a ‘1’ digit for 300 ms, and then stopping the dtmf stream.  However, when I run my SIP client script and send a call to it, I get the following output in console when my client tries to generate the dtmf tone:


ERROR:root:No dtmf generator at this time !


I’ve made sure that both my client and my PBX are using the same DTMF payload type (rfc2833) (I’ve set use_rfc2833_for_dtmf to true in my core object).  What is required in order for me to create a dtmf generator?  I am not finding much help in the Linphone Python documentation.




-          Ken C.


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