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From: | Kenneth Clive |
Subject: | [Linphone-users] No dtmf generator when attempting to play dtmf [Python] |
Date: | Wed, 16 Sep 2015 13:39:53 +0000 |
I am having trouble generating dtmf tones when I receive a call. Here is what my call_state_changed callback looks like (this is in Python): def call_state_changed(core, call, state, message): logging.warning("call_state_changed: " + str(state) + ", " + message) if state == linphone.CallState.IncomingReceived: print "***Incoming call on " + core.identity core.accept_call(call) time.sleep(10) # wait 10 seconds for audio to play elif state == linphone.CallState.Connected: core.start_dtmf_stream() core.play_dtmf(1,300) # press 1 for 300 ms to acknowledge the alert core.stop_dtmf_stream() print "***Call successfully answered on " + core.identity elif state == linphone.CallState.End: print "***Call successfully hung up on " + core.identity elif state == linphone.CallState.Error: logging.error("call_state_changed: " + core.identity + ", " + str(state) + ", " + message) When I am handling the linphone.CallState.Connected case, I am starting the dtmf stream, playing a ‘1’ digit for 300 ms, and then stopping the dtmf stream. However, when I run my SIP client script and send a call to it, I get the following
output in console when my client tries to generate the dtmf tone: ERROR:root:No dtmf generator at this time ! I’ve made sure that both my client and my PBX are using the same DTMF payload type (rfc2833) (I’ve set use_rfc2833_for_dtmf to true in my core object). What is required in order for me to create a dtmf generator? I am not finding much
help in the Linphone Python documentation. Thanks! -
Ken C. |
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