Re: [MIT-Scheme-users] SIGILL, Illegal instruction

[Elizabeth Barham]

Chris writes:

>    0x8089d39 <i386_initialize_no_fp+28>:      pushf

        eax            0x40346  262982
        ecx            0x346    838

>    0x8089d3a <i386_initialize_no_fp+29>:      pop    %eax

        eax            0x40346  262982
        ecx            0x346    838

>    0x8089d3b <i386_initialize_no_fp+30>:      xor    %ecx,%eax

        eax            0x40000  262144
        ecx            0x346    838

>    0x8089d3d <i386_initialize_no_fp+32>:      je     0x8089d9e 
> <no_cpuid_instr>

        eax            0x40000  262144
        ecx            0x346    838

>    0x8089d3f <i386_initialize_no_fp+34>:      push   %ecx

        eax            0x40000  262144
        ecx            0x346    838

>    0x8089d40 <i386_initialize_no_fp+35>:      popf

        eax            0x40000  262144
        ecx            0x346    838

>    0x8089d41 <i386_initialize_no_fp+36>:      movl   $0x1,0x80afcd4

        eax            0x40000  262144
        ecx            0x346    838

>    0x8089d4b <i386_initialize_no_fp+46>:      push   %ebx

        eax            0x40000  262144
        ecx            0x346    838

>    0x8089d4c <i386_initialize_no_fp+47>:      xor    %eax,%eax

        eax            0x0      0
        ecx            0x346    838

>    0x8089d4e <i386_initialize_no_fp+49>:      cpuid

        Program received signal SIGILL, Illegal instruction.
        0x08089d4e in i386_initialize_no_fp ()

>    0x8089d50 <i386_initialize_no_fp+51>:      cmp    $0x1,%eax
>    0x8089d53 <i386_initialize_no_fp+54>:      jl     0x8089d9d <not_amd_cpu>

Thank you,
Elizabeth